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```Date: Sat, 22 Apr 2000 20:57:34 -0400 (EDT)
Subject: SCEN103: Exam Review and Selected Answers

Attached below you will find numerical answers for some of the previous
SCEN103 midterm exam questions.  If you find any errors to typos please
let me know immediately.

Copies of the exams are available at
<http://www.physics.udel.edu/~watson/scen103/colloq2000/midtermresource.html>

There will be an informal exam review on Monday evening at 7pm in Sharp
Lab 122 for those interested.

George Watson                  |   Gosh darn the torpedoes,
Dept. of Physics & Astronomy   |     full speed ahead!
University of Delaware         |
ghw@udel.edu                   | http://www.physics.udel.edu/~watson
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April 7, 1999

2. \$3 per month, Assuming 30m "round-trip" wiring and \$0.07 per kWhr.

3. 20 A at 115 V provides 2300 W of power.  Withdrawing 1100 W leaves
1200 W available for hairdryer.

4a. 0.20 A
4b. 1.4 V
4c. 8%

5a. 14 W
5b. 0.9 ohm
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Jan. 26, 1998

1. 6.3 A left for blender at 115 V allows for 720 W.

5a. 9.0 ohm
5b. 60 %

6.  R2
7.  R1
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Oct. 17, 1996

1. Appliances all operating would draw 22 A.  Alternatively consider that
15 A at 115 V provides 1700 W max.  Fuse will blow.

3. 1.6 kA

6. 1.0 ohm

7. decrease
-----------------------------------------------------------------------
Mar. 19, 1996

2. 30 ohm

3. 20 A at 120 V provides 2400 W max.  Appliances would require 2580 W.
Fuse will blow.

6b. decrease
6c. decrease
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Oct. 31, 1995

4-1. 1,4 V
4-2. 0.5 ohm
4-4. 6.7%

5-2. 15 A at 110 V can provide 1650 W, two appliances together require
2200 W. Fuse will blow.
5-3. 20 A at 110 V can provide 2200 W, so both can just barely operate at
the same time.
```

 Comments, suggestions, or requests to ghw@udel.edu. "http://www.physics.udel.edu/~watson/scen103/colloq2000/announce/22.html" Last updated April 24, 2000. © George Watson, Univ. of Delaware, 2000.