The voltage across each resistor can now be found by applying Ohm's law to each resistor:
V1 = IR1 = (0.33 A)(6 ohm) = 2.0 V
V2 = IR2 = (0.33 A)(3 ohm) = 1.0 V
Note that the sum of the voltages across the two resistors is 3.0 V, equal to the voltage across the battery, as it must in this configuration.
A current of 0.33 A flows in all three circuit elements.
A voltage of 2.0 V appears across the 6 ohm resistor and a voltage of 1.0 V appears across the 3 ohm resistor.
Last updated Jan. 17, 1998.
Copyright George Watson, Univ. of Delaware, 1996.