An extra 3 ohms of resistance has been added to the circuit for a total of 9 ohms of resistance. Applying Ohm's law,

The voltage across each resistor can now be found by applying Ohm's law to each resistor:

**V _{1}** =

Note that the sum of the voltages across the two resistors is 3.0 V, equal to the voltage across the battery, as it must in this configuration.

**Answer:**

A current of 0.33 A flows in all three circuit elements.

A voltage of 2.0 V appears across the 6 ohm resistor and a voltage of 1.0 V appears across the 3 ohm resistor.

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Comments, suggestions, or requests to ghw@udel.edu.

"http://www.physics.udel.edu/~watson/scen103/circ3sol.html"

Last updated Jan. 17, 1998.

Copyright George Watson, Univ. of Delaware, 1996.