[Syllabus logo] Resistor Combinations

Series Combination:

[Schematic of series circuit]

Solution:
An extra 3 ohms of resistance has been added to the circuit for a total of 9 ohms of resistance. Applying Ohm's law,
I = V / R = (3 V ) / (9 ohm) = 0.33 A

The voltage across each resistor can now be found by applying Ohm's law to each resistor:
V1 = IR1 = (0.33 A)(6 ohm) = 2.0 V
V2 = IR2 = (0.33 A)(3 ohm) = 1.0 V
Note that the sum of the voltages across the two resistors is 3.0 V, equal to the voltage across the battery, as it must in this configuration.

Answer:
A current of 0.33 A flows in all three circuit elements.

A voltage of 2.0 V appears across the 6 ohm resistor and a voltage of 1.0 V appears across the 3 ohm resistor.


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Comments, suggestions, or requests to ghw@udel.edu.

"http://www.physics.udel.edu/~watson/scen103/circ3sol.html"
Last updated Jan. 17, 1998.
Copyright George Watson, Univ. of Delaware, 1996.