Applying Ohm's law,
I = V/R = (3 V) / (3 ohm) = 1.0 A
The 6 ohm resistor is similarly unaffected by the 3 ohm resistor; its current is the same as before, 0.5 A.
The current in the battery is the sum of the currents flowing in the two resistors; it provides 0.5 A for the 6 ohm resistor and 1.0 A for the 3 ohm resistor for a total of 1.5 A.
Note that the current through the 3 ohm resistor is twice that of the 6 ohm resistor; that branch has half the resistance.
A current of 0.5 A flows in the 6 ohm resistor, as before.
A current of 1.0 A flows in the 3 ohm resistor.
A current of 1.5 A flows in the battery, the sum of the currents above.
Last updated Jan. 7, 1998.
Copyright George Watson, Univ. of Delaware, 1996.