PHYS345 Electricity and Electronics

Quiz 1 Solution: Simple Circuits

The two resistors are in series thus the effective resistance of the circuit is 7.6 ohm. The current is (1.5 V)/(7.6 ohm) = 197 mA.

The terminal voltage of the battery is the same as the voltage across the lamp, the 7.0 ohm resistor, (0.197 A)(7.0 ohm) = 1.38 V.

The power dissipated by the lamp is P =IV =(197 mA)(1.38 V) = 272 mW.

Last updated Sept. 9, 1999.
Copyright George Watson, Univ. of Delaware, 1999.