## PHYS345 Electricity and Electronics

**Hint for S3.2b**
By inspection, left mesh current *I*_{1} is 6 A.

By inspection, right mesh current *I*_{3} is - 3 A.

The center mesh equation is 9 *I*_{2} - 3 *I*_{1} - 6 *I*_{3} = 18.

Solve for *I*_{2} and find the voltage difference across either of the center
branches.

"http://www.physics.udel.edu/~watson/phys345/protected/exercises/hints/S3-2b.html"

Last updated Sept. 9, 1999.

Copyright George Watson, Univ. of Delaware, 1999.