PHYS345 Electricity and Electronics

Hint for 4.52

Assigning the left and right nodal voltages as v1 and v2 respectively, the KCL at the right node yields:
(v2 - v1)/(-j20) + v2/40 + v2/(j20) = 0

Thanks to Dawn Cintavey for pointing out errors in the originally published hint!

Last updated Sept. 30, 1999.
Copyright George Watson, Univ. of Delaware, 1999.