PHYS345 Electricity and Electronics

Hints for 9/30 Assignment

Hint for 4.51

Labeling the left and right mesh currents as i1 and i2 respectively, the KVL for the first mesh yields:
i1(100 - j667) + i2(j667) = 15

Hint for 4.52

Assigning the left and right nodal voltages as v1 and v2 respectively, the KCL at the right node yields:
(v2 - v1)/(-j20) + v2/40 + v2/(j20) = 0

Last updated Oct. 2, 1999.
Copyright George Watson, Univ. of Delaware, 1999.