## PHYS345 Electricity and Electronics

**Hints for 9/28 Assignment**

**Hint for 7.14**
The impedance of the load is 18.2 ohm \/ -43.3.

The current through the source is 12.2 A \/ 41.4

**Hint for 7.16**

The unbalanced load impedance is 145 ohm \/ 36.9 deg.

*Harder way:* You may add a capacitor in parallel to this impedance and determine when the effective net reactance is zeroed.

*Easier way:* Evaluate the reactive power when unbalanced and use that quantity to determine what capacitive
reactance is required.

**Hint for 7.17**

Calculate the real and reactive power for each appliance and add to find the apparent power.

**Hint for 7.20**

w/o C: Q = -750 VAR

with C: Q = -330 VAR desired

What additional reactance is needed to provide the difference?

"http://www.physics.udel.edu/~watson/phys345/protected/exercises/hints/0928.html"

Last updated Sept. 29, 1999.

Copyright George Watson, Univ. of Delaware, 1999.