PHYS345 Electricity and Electronics
Hints for 9/9 Assignment
Hint for S3.1b
By inspection, left mesh current I1 is 2 A.
The right mesh equation is 6 Ix - 4 I1 = 10.
Hint for S3.2b
By inspection, left mesh current I1 is 6 A.
By inspection, right mesh current I3 is - 3 A.
The center mesh equation is 9 I2 - 3 I1 - 6 I3 = 18.
Solve for I2 and find the voltage difference across either of the center
Hint for 3.13
- Label the mesh currents as follows:
- I1 for the left mesh.
- I2 for the top right mesh.
- I3 for the bottom right mesh.
- The mesh equation for the left loop is then:
- 6 I1 - 2 I2 - 3 I3 = 2.
Last updated Sept. 9, 1999.
Copyright George Watson, Univ. of Delaware, 1999.