PHYS345 Electricity and Electronics

Answer for P8-19

The Thevenin resistance of (2+6.4+6.4) ohm =14.8 ohm and the input impedance of 50 ohm creates a voltage divider that reduces the amplifier input to V1 = 50/(14.8+50) Vt = (50/64.8) 42 mV = 32 mV.


"http://www.physics.udel.edu/~watson/phys345/protected/exercises/answers/P8-19.html"
Last updated Oct. 30, 1998.
Copyright George Watson, Univ. of Delaware, 1998.