## PHYS345 Electricity and Electronics

Detailed Mesh Analysis Example

The same circuit is used in the Detailed Multiloop Circuit Example.

Step 1: Replace any combination of resistors in series or parallel with their equivalent resistance. Here I simply use the result from the previous example.

Step 2: Choose clockwise mesh currents for each mesh and label accordingly.

Step 3: Write the mesh equation for each mesh. Here I suppress the "k" for each resistor; the final currents will be in milliamps.

 Left mesh: 11 I1 - 6 I2 = 9 Right mesh: - 6 I1 + 18 I2 = 9

Step 4: Solve the equations to obtain the values of the unknowns. Tackle the solution of the simultaneous equations in your preferred way.

Solution:
 I1 : 4/3 mA 1.33 mA I2 : 17/18 mA 0.94 mA

These results may be used to find any of the quantities of interest, as in the Detailed Multiloop Circuit Example.

"http://www.physics.udel.edu/~watson/phys345/examples/mesh-analysis.html"
Last updated Sept. 14, 1998.
Copyright George Watson, Univ. of Delaware, 1998.