## PHYS345 Electricity and Electronics

**Detailed Mesh Analysis Example**
The same circuit is used in the
Detailed Nodal Analysis Example.

**Step 1:** Replace any combination of resistors in series or parallel with their equivalent resistance.
Here I simply use the result from the previous example.

**Step 2:**
Choose clockwise mesh currents for each mesh and label accordingly.

**Step 3:**
Write the mesh equation for each mesh.
Here I suppress the "k" for each resistor; the final currents will be in milliamps.

Left mesh: |
11 *I*_{1} - 6 *I*_{2} = 9 |

Right mesh: |
- 6 *I*_{1} + 18 *I*_{2} = 9 |

**Step 4:**
Solve the equations to obtain the values of the unknowns.
Tackle the solution of the simultaneous equations in your preferred way.

**Solution:**
*I*_{1} : |
4/3 mA |
1.33 mA |

*I*_{2} : |
17/18 mA |
0.94 mA |

"http://www.physics.udel.edu/~watson/phys345/examples/mesh-analysis.html"

Last updated Sept. 8, 1999.

Copyright George Watson, Univ. of Delaware, 1998.