PHYS345 Electricity and Electronics

Hint for D3.1

By inspection, left mesh current I1 is 2 A.
The right mesh equation is 6 Ix - 4 I1 = 10.

Hint for D3.2

The nodal equation is
- 2 + V1/4 + (V1 + 10)/2 = 0.

Hint for D3.7

By inspection, left mesh current I1 is 6 A.
By inspection, right mesh current I3 is - 3 A.
The center mesh equation is 9 I2 - 3 I1 - 6 I3 = 18.

Solve for I2 and find the voltage difference across either of the center branches.

Hint for D3.8

The nodal equation is
- 6 + (V1 - 18)/3 + V1/6 - 3 = 0.


"http://www.physics.udel.edu/~watson/phys345/protected/exercises/hints/0910.html"
Last updated Sept. 15, 1998.
Copyright George Watson, Univ. of Delaware, 1998.