t = (L/R) ln(2)
For N=5, q = 5.85 microC.
For N=10, q = 5.52 microC.
For N=100, q = 1.93 microC.
Substitute this derivative and the one from the hint into Eq. 33.20 to find the final expression.
b) Beta is 11.4 rad/sec and omega is 176 rad/sec. When beta is much smaller than the omega, the fractional shift introduced by loss can be approximated by -(beta/omega)2/2. Thus the fractional shift in frequency is 0.2%.