PHYS208 Fundamentals of Physics II

Answer for Ch. 29, 5P

a) Magnetic force is to the east.

b) From classical kinetic energy formula, speed of electron is 6.49 x 107 m/s.
[This is 0.22 times the speed of light; corrected for relativistic effects, the speed would only change to 6.39 x 107 m/s, not much difference!]

The acceleration is 6.27 x 1014 m/s2.

c) The electron follows a circular path of radius 6.72 m.

The resulting deflection is 2.98 mm.

Answer for Ch. 29, 45E

Force is 28.2 N to the west.

Answer for Ch. 29, 46E

Current required is 467 mA.

Answer for Ch. 29, 53P

The required magnetic field is 0.10 T at an angle of 31 degrees from the vertical.

Answer for Ch. 29, 60P

The resultant force is vertical with magnitude


Last updated March 24, 1998.
Copyright George Watson, Univ. of Delaware, 1997.